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Thread: AP Chem help
04-15-2013, 01:19 PM #1
AP Chem help
i've been stuck on this question for forever.
I don't want the answer to this but i have a solution of methylamine and i need the pOH of the solution.
When i get x is that is the [OH-]
Then when i put it into
-log(x) do i have pH or pOH.
04-15-2013, 01:32 PM #2
It has been a few months since I have done any of this, but I believe you have the OH- ions here. If you want to reverse the process then 2nd log or 10^x is what you would do with the value from the -log. To get the pH from a pOH, just subtract the pOH from 14.
Edit: I didn't quite realize what you were asking until I read it over a few times. If you are trying to get the pH from the [OH-], you would up 10^[OH-] and that would give you your pOH and subtract that from 14 for the pH. To find the pOH from the [H3O+], just do the same.
Last edited by ChumLee; 04-15-2013 at 01:36 PM.
04-15-2013, 01:35 PM #3
04-15-2013, 01:40 PM #4
In 10^x, x would be the concentration of Hydronium ions or Hydroxide ions, then you would get either the pH or pOH by pressing enter.
04-15-2013, 01:45 PM #5
04-15-2013, 01:48 PM #6
04-15-2013, 01:51 PM #7
04-15-2013, 01:56 PM #8
Yeahhhhh...I'm no help there. It's been a while since I've done this stuff. Sorry. :P
04-15-2013, 01:56 PM #9
04-15-2013, 02:47 PM #10
Pm grey. He's a genius.